tag:blogger.com,1999:blog-756329316658223587.post8751394938443090787..comments2024-03-10T10:02:58.044+01:00Comments on Matemáticas na Rúa: Humor nun exame?JJhttp://www.blogger.com/profile/16829561981417320165noreply@blogger.comBlogger3125tag:blogger.com,1999:blog-756329316658223587.post-80896733678577582642011-06-24T13:43:06.635+02:002011-06-24T13:43:06.635+02:00Seguiré insistiendo hasta que los habilite.
Salud...Seguiré insistiendo hasta que los habilite.<br /><br />Saludos.Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-756329316658223587.post-85873005628852224802011-06-21T22:49:38.360+02:002011-06-21T22:49:38.360+02:00Pois era boa idea, rloca, non se me ocorrera, aínd...Pois era boa idea, rloca, non se me ocorrera, aínda que a fórmula de Herón non llela expliquei este ano. Con respecto ao latex(que esquecera comentar) o script que uso non funciona nos posts pois a etiqueta DIV non está permitida.JJhttps://www.blogger.com/profile/16829561981417320165noreply@blogger.comtag:blogger.com,1999:blog-756329316658223587.post-35667609825871852402011-06-21T21:36:55.453+02:002011-06-21T21:36:55.453+02:00Fórmula de Herón para el primer ejercicio:
$\sqrt...Fórmula de Herón para el primer ejercicio:<br /><br />$\sqrt {27 \cdot (27-21} \cdot (27-20) \cdot (27-13)$ = \frac {21 \cdot h}{2}$Anonymousnoreply@blogger.com